检查字符串是否包含列表中的任何字符串

Question

I am quite new to java and currently stuck and do not know how to proceed.

What I want to do is to check if a string contains any words from a list of words and if yes output them.

In my case all strings will have a similar text like this one (example with 5 mins):

Set timer to five minutes

or this one:

Timer five minutes

This is my current code with some comments what I am trying to do:

import java.util.stream.Stream; 

class GFG { 

// Driver code 
public static void main(String[] args) 
{ 

String example = Set timer to five minutes

    Stream<String> stream = Stream.of(("Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten") //The stream/array would be much bigger since I want to cover every number till 200 

//Now I thought I can use stream filter to check if example contains the word Timer and any of the words of the Stream and if it does I want to use the output to trigger something else

    if(stream.filter(example -> example .contains(NOTSUREWHATTOPUTHERE))) {
       //If detected that String contains Timer and Number, then create timer 
    } 
} 

Can anyone give me some advice/help?

regards

Answer 1

You can do it like this:

String[] words = { "Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten" };

String example = "Set timer to five minutes";

String exLower = example.toLowerCase();
if (Stream.of(words).anyMatch(word -> exLower.contains(word.toLowerCase()))) {
    //
}

That code will at least check correctly, even when words have different upper-/lower-case, but it fails if the text has a word embedded in another word, eg text "stone" will match because "one" is found.

To fix that, the "easiest" would be to convert the word list to a regex.

String[] words = { "Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten" };

String example = "Set timer to five minutes";

String regex = Stream.of(words).map(Pattern::quote)
        .collect(Collectors.joining("|", "(?i)\\b(?:", ")\\b"));
if (Pattern.compile(regex).matcher(example).find()) {
    //
}

Answer 2

The correct one would be

String example = "Set timer to five minutes";
Stream<String> stream = Stream.of("Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten");
if (stream.anyMatch(something -> example.contains(something))) {

}

You should give the lambda variable a different name other than example because that conflicts with the already existing local variable.
Additionally you can / should use anyMatch instead of filter + checking the length.

Or just:

if (stream.anyMatch(example::contains)) {