[英]Check if a string contains any of the strings from an List
我對 java 很陌生,目前卡住了,不知道如何繼續。
我想要做的是檢查一個字符串是否包含單詞列表中的任何單詞,如果是 output 它們。
在我的情況下,所有字符串都將具有類似的文本(例如 5 分鍾):
Set timer to five minutes
或者這個:
Timer five minutes
這是我當前的代碼,帶有一些我想要做的評論:
import java.util.stream.Stream;
class GFG {
// Driver code
public static void main(String[] args)
{
String example = Set timer to five minutes
Stream<String> stream = Stream.of(("Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten") //The stream/array would be much bigger since I want to cover every number till 200
//Now I thought I can use stream filter to check if example contains the word Timer and any of the words of the Stream and if it does I want to use the output to trigger something else
if(stream.filter(example -> example .contains(NOTSUREWHATTOPUTHERE))) {
//If detected that String contains Timer and Number, then create timer
}
}
誰能給我一些建議/幫助?
問候
你可以這樣做:
String[] words = { "Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten" };
String example = "Set timer to five minutes";
String exLower = example.toLowerCase();
if (Stream.of(words).anyMatch(word -> exLower.contains(word.toLowerCase()))) {
//
}
該代碼至少會正確檢查,即使單詞具有不同的大寫/小寫,但如果文本中嵌入了另一個單詞,則它會失敗,例如文本"stone"
將匹配,因為找到"one"
。
要解決這個問題,“最簡單”的方法是將單詞列表轉換為正則表達式。
String[] words = { "Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten" };
String example = "Set timer to five minutes";
String regex = Stream.of(words).map(Pattern::quote)
.collect(Collectors.joining("|", "(?i)\\b(?:", ")\\b"));
if (Pattern.compile(regex).matcher(example).find()) {
//
}
正確的應該是
String example = "Set timer to five minutes";
Stream<String> stream = Stream.of("Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten");
if (stream.anyMatch(something -> example.contains(something))) {
}
您應該為 lambda 變量指定一個不同於example
的名稱,因為這與已經存在的局部變量沖突。
此外,您可以/應該使用anyMatch
而不是filter
+ 檢查長度。
要不就:
if (stream.anyMatch(example::contains)) {
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