在python中，1, 2 == 1, 2是什么意思？

Question

Can someone explain output? I wanted to check for equality of two numbers but didn't work out properly.

Input: 1, 2 == 1, 2
Output: (1, False, 2)

Answer 1

You are creating a tuple with 3 elements, namely, 1 , 2 == 1 , and 2 . The first and last element are integer literals so it might not come as a surprise that their values in Python evaluate to 1 and 2 respectively. The element, 2 == 1 is a single expression that evaluates to False because 2 does not equal 1 .

If you are looking to check the equality of two tuples with two elements, (1,2) and (1,2) you must do (1, 2) == (1, 2) so Python knows which elements separated by commas to treat as a single element.

In the REPL you can figure this out by comparing what you have with

>>> (1, 2) == (1, 2)
True
>>> (1, 3) == (1, 2)
False
>>> (3, 1) == (2, 1)
False

Answer 2

You are making a tuple of 3 elements, int, boolean and int.

If you want a simutaneous comparison use

[1, 2] == [1, 2]

Answer 3

print 1, 2 == 1, 2

which is

print 1, False, 2 //since 1 not equal to 2

which will output

1 False 2

Answer 4

Actually 2==1 will give you false since 2 is not equal to one.So a better way of doing this is using if statements

a = 1
b = 2
if b > a:
  print(b + " is greater than " + a)
elif a == b:
print("a and b are equal")
else:
print("a is greater than b")

Answer 5

As per your code, it is a simple equality checking. It returns true if both the operands are true, in your case, it is 1 == 2 so it will return false as both are not the same. If you to compare them then add braces over them.

Answer 6

The order of operations is not what you think. == has a higher priority than the commas. So you are creating a 3-tuple with the following elements:

1
the result of the Boolean test to see whether 2 equals 1
2

This may be what you intend, try it:

>>> (1,2) == (1,2)
True