要元组的单独列表列表

Question

Input    : [['1538', '1'], [False], [True], ['firm']]
Output : [('1538', False, True, 'firm'),
          ('1', False, True, 'firm')]

lzip is giving only the first row

In [91]: lzip(*[['1538', '1'], [False], [True], ['firm']])
Out[91]: [('1538', False, True, 'firm')]

Also it expects all args to be an iterable. I wanted this to handle even if the input is like, [['1538', '1'], False, True, 'firm']

What is the easy way to do this

Answer 1

You can use itertools.product

from itertools import product
list(product(*[['1538', '1'], [False], [True], ['firm']]))
#[('1538', False, True, 'firm'), ('1', False, True, 'firm')]

Answer 2

Building upon ExplodingGayFish's answer , if you want to be able to handle the second case as well:

from itertools import product

Input = [['1538', '1'], [False], [True], ['firm']]
Input2 = [['1538', '1'], False, True, 'firm']

def sep(iterable):
    new_iter = (item if isinstance(item,list) else [item] for item in iterable)
    return list(product(*new_iter))

print(sep(Input))
print(sep(Input2))

Output:

[('1538', False, True, 'firm'), ('1', False, True, 'firm')]
[('1538', False, True, 'firm'), ('1', False, True, 'firm')]