我想从字典元素创建列表

Question

I have Nested dictionary something like this.

{'A': {'21-26': 2,
  '26-31': 7,
  '31-36': 3,
  '36-41': 2,
  '41-46': 0,
  '46-51': 0,
  'Above 51': 0},
 'B': {'21-26': 2,
  '26-31': 11,
  '31-36': 5,
  '36-41': 4,
  '41-46': 1,
  '46-51': 0,
  'Above 51': 3}}

And I want to create list by key from second dictionary. And i don't want duplicates in my list.

Required Output is

ls = ['21-26','26-31','31-36','36-41','41-46','46-51','Above 51']

Thank you for your time and consideration.

Answer 1

You can use:

>>> list(set(key for val in d.values() for key in val.keys()))
['21-26', '36-41', '31-36', '46-51', 'Above 51', '26-31', '41-46']

Where d is your dictionary.

Answer 2

Simple set comprehension, then convert to list. a is your dict.

list({k for v in a.values() for k in v.keys()}) 

Output ordering is random, but you can sort how you like.

Answer 3

Can you use pandas? IF so:

import pandas as pd
a = {'A': {'21-26': 2, '26-31': 7, '31-36': 3, '36-41': 2, '41-46': 0, '46-51': 0, 'Above 51': 0}, 'B': {'21-26': 2, '26-31': 11, '31-36': 5, '36-41': 4, '41-46': 1, '46-51': 0, 'Above 51': 3}}

pd.DataFrame(a).index.to_list()

output:

['21-26', '26-31', '31-36', '36-41', '41-46', '46-51', 'Above 51']

Answer 4

You can use chain.from_iterable() to chain inner dictionaries and dict.fromkeys() to remove duplicates:

from itertools import chain

c = chain.from_iterable(dct.values())
result = list(dict.fromkeys(c))