我有两个列表，我想从中创建一个字典。 但是我想为一个键存储多个值

Question

I have two list as below

idx = [344, 344, 590]
newx = [(257, 381), (260, 368), (514, 245)]

I used the below code to make dictionary but it neglected one value. I want to store multiple values with one key.

res = dict(zip(idx, newx))
print(res)

output looks like {344: (260, 368), 590: (514, 245)} but I want output to be {344: [(257, 381),(260, 368)], 590: [(514, 245)]}

Answer 1

Use a defaultdict:

from collections import defaultdict

idx = [344, 344, 590]
newx = [(257, 381), (260, 368), (514, 245)]

# default to empty list
res = defaultdict(list)
for k, v in zip(idx, newx):
    res[k].append(v)

# get rid of default value
res = dict(res)

Answer 2

You can not do that as dict objects have unique keys. You should just the use list of tuple:

idx = [344, 344, 590]
newx = [(257, 381), (260, 368), (514, 245)]

res = zip(idx, newx)
print(list(res))

If you want to access all the values based on the key, use collections.defaultdict

Answer 3

I believe this will do what you want. Bonus, this won't require an import.

I hope this helps.

res = {}
for k, v in zip(idx, newx):
    if k in res:
        res[k].append(v)
    else:
        res[k] = [v]

Answer 4

I have two list as below

idx = [344, 344, 590]
newx = [(257, 381), (260, 368), (514, 245)]

I used the below code to make dictionary but it neglected one value. I want to store multiple values with one key.

res = dict(zip(idx, newx))
print(res)

output looks like {344: (260, 368), 590: (514, 245)} but I want output to be {344: [(257, 381),(260, 368)], 590: [(514, 245)]}