如何在 PHP (laravel) 中模拟没有类的函数？

Question

I have a Function Which is loaded by composer autoload

 "autoload": { "files": [ "app/Helpers/SmsHelper.php", ] },

This File Has a smsHelper Function Which Can send SMS.

 <?php if (!function_exists('sendSmsHelper')) { function sendSmsHelper($msisdn, $message) { ..... Codes } }

One Of My class use this Helper and i want to write test for this class. could some one tell me how to mock this function? because i don't want to send SMS in testing mode

Answer 1

As I dont see any answers I decided to Wrote about some of my researches result: I know these are not the right answers maybe but will work

First Solution (not good one): if you are using a function in your class and want to writing a test for that class ! for mocking this type of functions you can set your test class NameSpace equal to the class that you want to writing test for, then you can write a function exactly the same name of specific function out of the class in your .php file.

for example : you use date() in your class and want to mock it to return your String instead of date

 <?php //namespace Tests\\Unit; change this name space to that class you want to write test for namespace yourclass namespace; use Mockery\\Mock; function date() { return "2019/12/17 01:00:00"; } class yourNameTest extends TestCase { ...... you test codes }

Second Solution for the functions you created ( like my smsHelper ) :

I added a SwitchCase in my smsHelper function which will check if App is on Testing mode or not , if its on testing mode I'm going to return true;

 function smsHelper() { if (!App::runningUnitTests()) { ....... my codes } else { return true; } }