在 jasmine 单元测试中，预期 '^169.254$' 为 /^169.254$/
[英]Expected '^169.254$' to be /^169.254$/ in jasmine unit testing
问题描述
I am new to Angular, Karma, Jasmine test framework.
我是 Angular、Karma、Jasmine 测试框架的新手。 I am getting the following error.我收到以下错误。 It was working fine.它工作正常。 After upgrade to angular 7, I am getting the below error.升级到 angular 7 后，出现以下错误。
[1A[2K[31mElectron 2.0.2 (Node 8.9.3) HostComponent should call ipAddressPattern and check IP bad IP FAILED[39m Expected '^169.254$' to be /^169.254$/.
My code is given below.我的代码如下。
In unit test在单元测试中
it("should call ipAddressPattern and check IP bad IP", () => {
expect(component.ipAddressPattern("169.254.11.11")).toBe(new RegExp(CommonConstants.BAD_IP_ADDRESS_PATTERN));
});
Earlier code was like this expect(component.ipAddressPattern("169.254.11.11")).toBe(CommonConstants.BAD_IP_ADDRESS_PATTERN);早期的代码是这样的expect(component.ipAddressPattern("169.254.11.11")).toBe(CommonConstants.BAD_IP_ADDRESS_PATTERN); and it was working.它正在工作。 After upgrade it gave compilation issue.升级后出现编译问题。 So I changed to expect(component.ipAddressPattern("169.254.11.11")).toBe(new RegExp(CommonConstants.BAD_IP_ADDRESS_PATTERN)) In the common constant class, the code is given below.于是我改成expect(component.ipAddressPattern("169.254.11.11")).toBe(new RegExp(CommonConstants.BAD_IP_ADDRESS_PATTERN))公共常量类中，代码如下。
public static readonly BAD_IP_ADDRESS_PATTERN: string = "^169\.254$";
In other classes, the code is given below.在其他类中，代码如下。
public ipAddressPattern(ipAddress: string): RegExp {
return CommonUtil.isBadIPAddress(ipAddress);
}
In CommonUtil class, the code is given below.在 CommonUtil 类中，代码如下。
public static isBadIPAddress(ipAddress: string): any {
if (ipAddress) {
if (ipAddress.startsWith(CommonConstants.BAD_IP_ADDRESS)) {
return CommonConstants.BAD_IP_ADDRESS_PATTERN;
} else {
return ValidationPatterns.IP_ADDRESS;
}
}
}
Please suggest me how to fix this issue.请建议我如何解决这个问题。
3 个解决方案
解决方案1
1 2019-12-10 18:30:03
You need to remove the call to new RegExp() .您需要删除对new RegExp()的调用。 That's going to return a new RegExp object each time, causing the test to fail.每次都会返回一个新的RegExp对象，导致测试失败。
To fix the compilation error, you need to correct the return type of ipAddressPattern .要修复编译错误，您需要更正ipAddressPattern的返回类型。 You're not returning a RegExp object, you're returning a string .您不是返回RegExp对象，而是返回string 。
So the signature needs to be: public ipAddressPattern(ipAddress: string): string所以签名需要是： public ipAddressPattern(ipAddress: string): string
解决方案2
0 2019-12-10 18:10:30
在JavaScript中， String.prototype.startsWith方法（@line 3在CommonUtil类）期待一个原始字符串，而不是一个正则表达式（字符串格式）。
expect(component.ipAddressPattern("169.254.11.11").toString()).toBe(new RegExp(CommonConstants.BAD_IP_ADDRESS_PATTERN).toString().replace(/^\\/|\\/$/g, ''))
解决方案3
0 2019-12-11 08:57:23
When I added "@types/jasmine": "^2.8.7", , in devDependencies, the problem got solved.当我在 devDependencies 中添加"@types/jasmine": "^2.8.7", ，问题就解决了。 So I did like this.所以我喜欢这个。
"devDependencies": {
"@angular/compiler-cli": "^7.2.0",
"@angular/language-service": "~7.2.0",
"@types/jasminewd2": "~2.0.3",
"@types/core-js": "^0.9.46",
"@types/jasmine": "^2.8.7",
... other modules ...
}
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