Java中从System.in获取int数组的简单方法

Question

The user types in System.in this

1 2 3 4 44 50 and so on

I need to get int array from it, so my solution is:

import java.util.Scanner;
public class Program
{
    public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);
        String tempString = in.nextLine();
        int tempArray[] = tempString.split(" ");
        result[] = tempArray(tempArray.length);

        for(int i=0; i<result.length; i++)
        {
            result[i] = Integer.parseInt(tempArray[i]);
        }
    }
}

Is there a way to simplify the code?

Answer 1

使用Stream可以在一行中完成：

int[] arr = Arrays.stream(in.nextLine().split(" ")).mapToInt(Integer::parseInt).toArray();

Answer 2

List<Integer> integersList = Stream.of("1 2 3 4 44 50".split(" "))
      .map(Integer::parseInt)
      .collect(Collectors.toList());

Also it can be usefull to remove redundant spaces

List<Integer> integersList = Stream
        .of("1 2 3 4 44 50".trim().replaceAll(" +", " ").split(" "))
        .map(Integer::parseInt)
        .collect(Collectors.toList());