我需要我的数组返回并数组返回另一个变量，同时还包括它以前的数组成员，不知道如何去做

Question

This is the test code that it's supposed to pass

function makeArray() {
    const array = [];
    const t = 10;

    for (let i = 0; i < t; i++) {
        array.push("I am a strange loop.");
    }

    return [array, t];
}

describe('loops', () => {
    jsdom({
        src: fs.readFileSync(path.resolve(__dirname, '..', 'loops.js'), 'utf-8'),
    });

    describe('forLoop(array)', () => {
        it('adds `"I am ${i} strange loop${i === 0 ? \'\' : \'s\'}."` to an array 25 times', () => {
            const [array, t] = makeArray();
            const strangeArray = forLoop(array);
            const testArray = strangeArray.slice(array.length);

            const first = "I am 1 strange loop.";
            const rest = "I am 24 strange loops.";

            expect(strangeArray[11]).to.equal(first);
            expect(strangeArray[34]).to.equal(rest);
            expect(strangeArray.length).to.equal(t + 25);
        });
    });
});

this is my code to return the function to strangeArray what I am thinking is that 35 is the total number of members in the array and as the test pass requires me to have 'expect(strangeArray[11]).to.equal(first)' 11th value to be equal to my function return as "I am 1 strange loop."

function forLoop(array) {
    for (let i = 0; i < 35; i++) {
        if (array[i] === "I am a strange loop.") {
            return;
        }
        else {
            array.push("I am ${i} strange loops.");
        }
    }
    return [array,i];
}

Answer 1

Not sure what you mean exactly but I guess you just want the test to pass? The problem is that the first loop has 'loop' as singular and your indexes don't work either since they would start at 11. That's why your code doesn't work. You can just push to the original array.

function forLoop(array){
  for(let i = 0; i < 25; i++){
    array.push(`I am ${i} strange loop${i > 1 ? '' : 's'}.`)
  }
  return array
}