如何在 ARM aarch64 GCC 内联汇编中使用 32 位 w 寄存器？

Question

I can use 64-bit registers for example as in:

#include <assert.h>
#include <inttypes.h>

int main(void) {
    uint64_t io = 1;
    __asm__ (
        "add %[io], %[io], 1;"
        : [io] "+r" (io)
        :
        :
    );
    assert(io == 2);
}

which compiles and disassembles with:

aarch64-linux-gnu-gcc -ggdb3 -o main.out main.c
gdb-multiarch -batch -ex 'disassemble/rs main' main.out

to a 64-bit register as expected:

6           __asm__ (
   0x0000000000000744 <+16>:    a0 0f 40 f9     ldr     x0, [x29, #24]
   0x0000000000000748 <+20>:    00 04 00 91     add     x0, x0, #0x1
   0x000000000000074c <+24>:    a0 0f 00 f9     str     x0, [x29, #24]

How to use 32-bit registers such as w0 instead?

Tested on Ubuntu 18.04, GCC 7.4.0.

Answer 1

It can be done by adding the w in front of the % , eg:

#include <assert.h>
#include <inttypes.h>

int main(void) {
    uint32_t io = 1;
    __asm__ (
        "add %w[io], %w[io], 1;"
        : [io] "+r" (io)
        :
        :
    );
    assert(io == 2);
}

which now disassembles to the desired 32-bit version:

6           __asm__ (
   0x0000000000000744 <+16>:    a0 1f 40 b9     ldr     w0, [x29, #28]
   0x0000000000000748 <+20>:    00 04 00 11     add     w0, w0, #0x1
   0x000000000000074c <+24>:    a0 1f 00 b9     str     w0, [x29, #28]

This could have been somewhat guessed from: http://infocenter.arm.com/help/index.jsp?topic=/com.arm.doc.100067_0612_00_en/qjl1517569411293.html since the ARM compiler 6 is LLVM based, and LLVM syntax is mostly GCC based.