在 C++ 中初始化变量的 = 和 {} 语法之间的区别

Question

I have read quite a few C++ codes, and I have come across two methods of initialising a variable.

Method 1:

int score = 0;

Method 2:

int score {};

I know that int score {}; will initialise the score to 0, and so will int score = 0;

What is the difference between these two? I have read initialization: parenthesis vs. equals sign but that does not answer my question. I wish to know what is the difference between equal sign and curly brackets , not parenthesis. Which one should be used in which case?

Answer 1

int score = 0; performs copy initialization , as the effect, score is initialized to the specified value 0 .

Otherwise (if neither T nor the type of other are class types), standard conversions are used, if necessary, to convert the value of other to the cv-unqualified version of T .

int score {}; performsvalue initialization with braced initializer, which was supported since C++11, as the effect,

otherwise, the object is zero-initialized .

score is of built-in type int , it's zero-initialized at last, ie initialized to 0 .

If T is a scalar type, the object's initial value is the integral constant zero explicitly converted to T .

Answer 2

You may have some interest in ISO/IEC 14882 8.5.1. It will tell you that a brace-or-equal-initializer can be assignment-expression or braced-init-list . In Method2, you are using an default initializer on a scalar type, witch should be set to zero.