[英]Integrate exponential function using sympy
I am trying to integrate e^(-x)
from 0
to 1
using sympy
but I am getting the following error:我正在尝试使用
sympy
将e^(-x)
从0
集成到1
但出现以下错误:
ValueError: Invalid limits given: ((exp(-x), 0, 1),)
Here is my code:这是我的代码:
from sympy import *
x = Symbol('x')
exact_value = integrate(exp(-x), (exp(-x), 0, 1))
Following the documentation the only problem is the tuple you establish as a limit (exp(-x), 0, 1) , since it has to be (x, 0, 1) following the previously mentioned structure.按照 文档,唯一的问题是您建立的元组作为限制(exp(-x), 0, 1) ,因为它必须是(x, 0, 1)遵循前面提到的结构。
So the edited code would be:所以编辑后的代码将是:
from sympy import *
x = Symbol('x')
exact_value = integrate(exp(-x), (x, 0, 1))
I'm pretty sure you want to integrate over x, not e^-x, so that would be:我很确定你想对 x 进行积分,而不是 e^-x,所以这将是:
exact_value = integrate(exp(-x), (x, 0, 1))
The results is:结果是:
1 - exp(-1)
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