[英]Pandas: setting value in a multi-indexed dataframe
I would like to set a value in a multi-indexed DataFrame.我想在多索引 DataFrame 中设置一个值。 Here is an example:
下面是一个例子:
import pandas as pd
df = pd.DataFrame([[1, 'a' , 1], [1, 'b', 2], [2, 'a', 3]], columns=['x', 'y', 'z'])
df.set_index(['x','y'], inplace=True)
df
gives:给出:
z
x y
1 a 1
b 2
2 a 3
and then进而
df.loc[(2,'b')] = 4
df
gives给
z b
x y
1 a 1 NaN
b 2 NaN
2 a 3 4.0
instead of代替
z
x y
1 a 1
b 2
2 a 3
b 4
So apparently, Pandas does not understand that the dataframe is multi-indexed and it interprets [(2,'b')]
as row 2 and column 'b', as if I had written df.loc[2,'b']
.显然,Pandas 不明白数据框是多索引的,它将
[(2,'b')]
为第 2 行和列 'b',就好像我写了df.loc[2,'b']
.
How can I achieve what I want ?我怎样才能实现我想要的?
Additionally, why is the integer 4 converted into a float ?另外,为什么整数 4 转换为浮点数?
Thanks.谢谢。
Also is necessary specify column z
:还需要指定列
z
:
df.loc[(2,'b'), 'z'] = 4
print (df)
z
x y
1 a 1.0
b 2.0
2 a 3.0
b 4.0
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.