python确保单词大写

Question

I'm trying to make sure that every word that is typed is uppercased as in ABC. The code I'm working with is this

abbreviate=input("Abbreviation: ")
words=abbreviate[0:6]
numbers = abbreviate[6:8]
if len(abbreviate)==9:
    if words.isalpha: #I think it's also possible to use.if str(words)?
        if words.isupper: #(i did upper first, what is the difference?)
            if int(numbers):
                print("correct")
            else:
                 print("wrong, you need numbers")
        else:
             print("wrong, all words are supposed to be uppercase")
    else:
         print("wrong, it needs to be words(alphabet)") 
else:
     print("wrong, the length needs to be 8")    

QWERTY567 should be correct. qwerty567 should be incorrect. How do I go on doing this?

qwerty333 012345678

Answer 1

str.isalpha and str.isupper are methods . You need to call them to get a result:

if words.isalpha():
    if words.isupper():

---

About your comments

I think it's also possible to use if str(words) ?

No, str(words) would do nothing.input() returns a string, so words is already a string.

I did upper first, what is the difference?

str.upper converts a string to uppercase, eg 'a'.upper() == 'A'

---

By the way

int() doesn't return a Boolean. It might be better to use str.isnumeric to check if numbers is numeric instead.

It's simpler to use guard clauses than nested conditionals:

if len(abbreviate) != 9:
    print("wrong, the length needs to be 9")
elif not words.isalpha():
    print("wrong, the abbreviation must be alphabetic")
...
else:
    print("correct")

Answer 2

IIUC In order to just verify, whether first 5 characters are uppercase letters, and next 4 are digits, you can do:

import re

abbreviate=input("Abbreviation: ")

if(re.match(r"^[A-Z]{5}\d{4}", abbreviate)):
    print("correct!")
else:
    print("wrong!")

If moreover you want to ensure it's only 9 characters in total (ie input consists of exactly 5 uppercase letters first, then 4 digits) you can do:

import re

abbreviate=input("Abbreviation: ")

if(re.match(r"^[A-Z]{5}\d{4}$", abbreviate)):
    print("correct!")
else:
    print("wrong!")

Answer 3

Use a regular expression:

^[A-Z0-9]+$

See a demo on regex101.com .

Answer 4

If you have all letters and then at a certain index, you have all numbers, I would suggest:

abbreviation=input("Abbreviation: ")
i = len(abbreviation)
for n, char in enumerate(abbreviation):
    if char.isalpha() and char.isupper():
        pass
    else:
        i = n
        break
for char in abbreviation[i:]:
    if char.isnumeric():
        pass
    else:
        print('Wrong')

https://www.geeksforgeeks.org/python-string-isnumeric-application/

https://www.geeksforgeeks.org/isupper-islower-lower-upper-python-applications/

You find the first non-lowercase letter, and then everything after it should be all numeric. If you need at least 1 uppercase letter, you can also modify that. Please tell me if you have questions!

Answer 5

如果 abbreviate 的值为 'QWERTY567'，那么您应该使用words = abbreviate[0:6] 、 numbers = abbreviate[6:8] 、 isalpha()和isupper()来编辑您的代码以使其工作。