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根据列表中的另一列内容创建新的列值

[英]Create a new column value based on another column content from a list

I am trying to create a new variable called "region" based on the names of countries in Africa in another variable.我正在尝试根据另一个变量中非洲国家的名称创建一个名为“区域”的新变量。 I have a list of all the African countries (two shown here as an example) but I have am having encountering errors.我有一个所有非洲国家的列表(这里以两个为例),但我遇到了错误。



def africa(x):
  if africalist in x:
    return 'African region'
  else:
    return 'Not African region'


df['region'] = ''

df.region= df.countries.apply(africa)

I'm getting :我越来越 :

'in ' requires string as left operand, not list 'in ' 需要字符串作为左操作数,而不是列表

I recommend you see When should I want to use apply .我建议您查看When should I want to use apply

You could use:你可以使用:

df['region'] = df['countries'].isin(africalist).map({True:'African region',
                                                     False:'Not African region'})

or或者

df['region'] = np.where(df['countries'].isin(africalist),
                        'African region',
                        'Not African region')

Your condition is wrong.你的条件不对。

The correct manner is正确的做法是

if element in list_of_elements:

So, changing the function africa results in:因此,更改功能africa导致:

def africa(x):
  if x in africalist:
    return 'African region'
  else:
    return 'Not African region'

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