[英]Python String: How to parse string and find specific String index?
I want to create a list of tuples, where I want:我想在我想要的地方创建一个元组列表:
# String
input= "M i n d"
# List of tuple
output = [(0, 3), (4, 9), (10, 18), (19, 19)]
I was able to write this logic(with an error in the last tuple), but feel that there must be a smarter way of writing this.我能够编写这个逻辑(在最后一个元组中有错误),但觉得必须有一种更聪明的方式来编写它。 Any idea?任何的想法?
string = "M i n d"
coltuple = []
for a in string:
if a.isalpha() == True:
start = string.index(a)
next_string = string[(start + 1) :]
if next_string:
for b in next_string:
if b.isalpha() == True:
end = string.index(b) - 1
print("End:", end)
break
else:
end = len(string) - 1
coltuple += [(start, end)]
print(coltuple)
This could be solved using the re
module.这可以使用re
模块解决。
import re
L = []
string = "M i n d"
pat = re.compile(r'\S+\s*')
for token in pat.finditer(string):
L.append((token.start(), token.end()-1))
print(L)
Prints:印刷:
[(0, 3), (4, 9), (10, 18), (19, 19)]
If you are going to use these values to index into the string, you might be better off using token.end()
rather than token.end()-1
.如果您打算使用这些值索引到字符串中,最好使用token.end()
而不是token.end()-1
。
Note: removed capturing parentheses from the regular exp.注意:从常规 exp 中删除了捕获括号。 It was r'(\\S+\\s*)
它是r'(\\S+\\s*)
This is what I came up with:这就是我想出的:
inputString= "M i n d"
alphaIndexes = []
alphaTuples = []
# Loop over range based on length of input
for i in range(0, len(inputString)):
# if its alpha
if inputString[i].isalpha() == True:
print("Alpha at {}".format(i))
# append it to list of indexes
alphaIndexes.append(i)
# Loop over range based on length of all found alphas
# minus one since we will create pairs
for i in range(0, len(alphaIndexes)-1):
# Append to list o alpha tuples tuple of
# current index and next index but substract that next one by one
alphaTuples.append((alphaIndexes[i], alphaIndexes[i+1]-1))
print(alphaTuples)
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