[英]Python String: How to parse string and find specific String index?
我想在我想要的地方創建一個元組列表:
# String
input= "M i n d"
# List of tuple
output = [(0, 3), (4, 9), (10, 18), (19, 19)]
我能夠編寫這個邏輯(在最后一個元組中有錯誤),但覺得必須有一種更聰明的方式來編寫它。 任何的想法?
string = "M i n d"
coltuple = []
for a in string:
if a.isalpha() == True:
start = string.index(a)
next_string = string[(start + 1) :]
if next_string:
for b in next_string:
if b.isalpha() == True:
end = string.index(b) - 1
print("End:", end)
break
else:
end = len(string) - 1
coltuple += [(start, end)]
print(coltuple)
這可以使用re
模塊解決。
import re
L = []
string = "M i n d"
pat = re.compile(r'\S+\s*')
for token in pat.finditer(string):
L.append((token.start(), token.end()-1))
print(L)
印刷:
[(0, 3), (4, 9), (10, 18), (19, 19)]
如果您打算使用這些值索引到字符串中,最好使用token.end()
而不是token.end()-1
。
注意:從常規 exp 中刪除了捕獲括號。 它是r'(\\S+\\s*)
這就是我想出的:
inputString= "M i n d"
alphaIndexes = []
alphaTuples = []
# Loop over range based on length of input
for i in range(0, len(inputString)):
# if its alpha
if inputString[i].isalpha() == True:
print("Alpha at {}".format(i))
# append it to list of indexes
alphaIndexes.append(i)
# Loop over range based on length of all found alphas
# minus one since we will create pairs
for i in range(0, len(alphaIndexes)-1):
# Append to list o alpha tuples tuple of
# current index and next index but substract that next one by one
alphaTuples.append((alphaIndexes[i], alphaIndexes[i+1]-1))
print(alphaTuples)
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