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SELECT WHERE LIKE 返回不完整的结果，原因不是变音符号

[英]SELECT WHERE LIKE returns incomplete results and the reason is not diacritics

 原文  2020-01-21 19:51:49  0   1    sql/ diacritics/ collate/ hidden-characters

问题描述

I am searching for results WHERE name LIKE '%Soucek%' (or I tried '%Souček%' or '%Soućek%' . I get one result. (I set the whole column to be COLLATE SQL_Latin1_General_CP1251_CI_AS ). If I search for '%Sou_ek%' i get all results there are. I dont understand what is going on. Do you have an idea?我正在搜索WHERE name LIKE '%Soucek%'结果（或者我尝试'%Souček%'或'%Soućek%' 。我得到一个结果。（我将整个列设置为COLLATE SQL_Latin1_General_CP1251_CI_AS ）。如果我搜索'%Sou_ek%'我得到了所有结果。我不明白发生了什么。你有什么想法吗？

1 个解决方案

解决方案1
 1  2020-01-21 22:33:24

Consider using AI : "Accent Insensitive" instead of AS : "Accent Sensitive".考虑使用AI ：“Accent Insensitive”而不是AS ：“Accent Sensitive”。

Also, make sure that both sides have the same collation to avoid errors or further coercions:此外，确保双方具有相同的排序规则以避免错误或进一步的强制转换：

WHERE name COLLATE Latin1_General_CI_AI Like '%Soucek%' COLLATE Latin1_General_CI_AI

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