您可以在列表上使用 Filter() 函数从更大的列表中创建一个新列表吗？

Question

I would be using the list and filter functions to create a new list containing only the odd length stock tickers. I have used lambda before doing something similar with numbers but can't seem to translate it to words. My code is below..

list1 = ["GOOGL", "IBM", "AAPL", "FB", "M", "WMT"]

list(filter(lambda item: item[0] == "odd", list1))

I want the output to be all odd length stock tickers

['GOOGL','IBM', 'M', 'WMT']

Answer 1

With filter

print(list(filter(lambda x: len(x) % 2 == 1, list1)))

With list comprehension

print([i for i in list1 if len(i)%2==1])

Output:

['GOOGL', 'IBM', 'M', 'WMT']