在Python中查找具有特定总数的列

Question

If:

sum(list(map(lambda x : sum(len(y) for y in x.split()), df['column2'].iloc[3])))

gets the total character in row number 3 of column number 2 in pandas dataframe df , then how to find the column that has a certain total number (for example: which index column has the total number of character of 43,382) ?

EDITED : I tried this rather long code:

df.loc[df['column2'] == (sum(list(map(lambda x : sum(len(y) for y in x.split()), df['column2'])))).isin('43382')]

but I got error message:

AttributeError: 'int' object has no attribute 'isin'

This is how my dataframe df looks like"

column1      column2                                            column3
amsterdam    school yeah right backtic escapes sport swimming   2016
rotterdam    nope yeah                                          2012
thehague     i now i can fly no you cannot swimming rope        2010
amsterdam    sport cycling in the winter makes me               2019

Answer 1

Can you try .isin(['43382']) .

Hope this helps.

Answer 2

尝试使用eq代替：

print(df[(sum(list(map(lambda x : sum(len(y) for y in x.split()), df['column2'])))) == ('43382')].dropna())

Answer 3

I figured it out by summing all the characters for each rows and return it to a new column = column4 :

df['column4'] = df['column2'].apply(lambda x: sum(len(y) for y in x.split()))

and then simply just look at the desire character's total count with this code:

df[df['column4']== 43382]