我不能停止我的“程序”到特定的打印，它只是继续

Question

There is an issue I'm having, it's a small story I'm, this has been frustrating me for hours now, help me!

if qsg_1 == "A":
    print ("Amazing, let's begin...")
elif qsg_1 == "B":
    print ("Goodbye, sinner.")

print(".")
print(".")
print(".")
print(".")
print(".")
print(".")
print("A tree is behind you.")

This seemed fine to me, but whenever I went and chose option B after opening the .py, this happened:

Okay user. Would you like to start this amazing journey?
[A] No. [B] Yes. [A/B]: B
Goodbye, sinner.
.
.
.
.
.
.
A tree is behind you.

I want to stop the "elif qsg_1 == "B": to print ("Goodbye, sinner."). I have tried to, although it's as if B was A, so even the:

print(".")
print(".")
print(".")
print(".")
print(".")
print(".")
print("A tree is behind you.")

appears, which has been getting me for hours now, I want the B option to end at print ("Goodbye, sinner") whenever I choose it, how do I do that? Help!

Answer 1

Python uses indentation to control what gets executed when. Consider the following:

if qsg_1 == "A":
    print ("Amazing, let's begin...")
    print(".")
    print(".")
    print(".")
    print(".")
    print(".")
    print(".")
    print("A tree is behind you.")
elif qsg_1 == "B":
    print ("Goodbye, sinner.")

Here, many print statements are under condition A, indented, so it is a good visual way to show what happens if condition A holds. The same for B.

Answer 2

Put you code to function and add return after printing B case

def my_fn():
    if qsg_1 == "A":
        print ("Amazing, let's begin...")
    elif qsg_1 == "B":
        print ("Goodbye, sinner.")
        return

    print(".")
    print(".")
    print(".")
    print(".")
    print(".")
    print(".")
    print("A tree is behind you.")


my_fn()