我可以以某种方式最小化 C# 中的 7-zip 输出/日志吗？

Question

I am using this code to compress folders:

ProcessStartInfo p = new ProcessStartInfo();
                        p.FileName = @"C:\Program Files\7-Zip\7z.exe";
                        p.Arguments = "a -t7z \"" + targetName + "\" \"" + item.ToString() + "\" -mx=9";
                        p.WindowStyle = ProcessWindowStyle.Minimized;
                        Process x = Process.Start(p);
                        x.WaitForExit();
                        Directory.Delete(dirPath + "\\" + item.Name, true);

When the app is compiling I get this output:

7-Zip 19.00 (x64) : Copyright (c) 1999-2018 Igor Pavlov : 2019-02-21

Open archive: C:\a\b\folders\compress.7z
--
Path = C:\a\b\folders\compress.7z
Type = 7z
Physical Size = 881619
Headers Size = 273
Method = LZMA2:23
Solid = +
Blocks = 1

    Scanning the drive:
    1 folder, 2 files, 8258668 bytes (8066 KiB)

    Updating archive: C:\a\b\folders\compress.7z

    Add new data to archive: 1 folder, 2 files, 8258668 bytes (8066 KiB)

     60% U Folder\thisisatext.txt

But I only want this: 60% U Folder\\thisisatext.txt Can I do this somehow? Thanks for any response.

Answer 1

If you set your process's standard output to redirect, like so:

p.RedirectStandardOutput = true;

( read more about this here )

You can then read 7 Zips output into a stream reader:

var reader = x.StandardOutput;
var output = reader.ReadToEnd();

Now that your programs output is stored in a string you can get your 60% value back. If it is always the last line of the output you could use Linq to get it:

var lastLine = output.Split('\n').Last().Trim();
Console.WriteLine(lastLine); // 60% U Folder\\thisisatext.txt"

In this case, we are splitting the lines of the output into an array .Split('\\n') then selecting the last line .Last() . We then remove any whitespace that might be before or after the string using .Trim() .