如何在整数中每 200 打印一个 X？

Question

My code:

x = [232,  456, 1024 , 245]
x_ = []
for i in range (0, len(x)):
    while x[i] >= 200:
        x_.insert(x[i], 'X')
        x[i] = x[i] - 200
print(x_)

Output: ['X', 'X', 'X', 'X', 'X', 'X', 'X', 'X', 'X']

Wanted Output: ['X', 'XX', 'XXXXX','X']

I essentially want to insert an X for every 200 in the element. So if an element in the list is let's say 456, the new list will have 'XX' in x_[2].

Answer 1

您可以将'X'乘以除以 200 的元素：

x_ = ['X' * (y // 200) for y in x]

Answer 2

You are currently inserting new 'X' in the list instead of appending your current entry. If you want to keep your structure try:

x_ = []
for i in range (0, len(x)):
    xs = 'X'
    x[i] -= 200
    while x[i] >= 200:
        xs += 'X'
        x[i] -= 200
    x_.append(xs)
print(x_)