.clean 和 .strip 长字符串的最佳方法？

Question

Desired Outcome Is = ["This", "is", "a", "random", "sentence"]

text = "Th,is is a? random!! sentence..."  # Eddied, added comma inside word 

clean_text = text.split()

for clean in clean_text:

    double_clean_text = clean.strip(",.!?")

    print(double_clean_text)

Managed to clean, but how do I get it all back to list??

Is this is efficient way to do it?

Answer 1

您可以执行以下操作：

print(" ".join([clean.strip(",.!?") for clean in clean_text]))

Answer 2

您可以使用列表理解：

print([t.strip(",.!?") for t in text.split()])

Answer 3

Try this:

clean_text = text.split()
print([clean.strip(",.!?") for clean in clean_text])

OR

clean_text = text.split()
res = []
for clean in clean_text:
    double_clean_text = clean.strip(",.!?")
    res.append(double_clean_text)
print(res)

Answer 4

I would recommend you to use regular expression "\\w+" to find all words:

import re

result = re.findall("\w+", text)

Answer 5

Instead of assigning to a new variable, assign the cleaned result back to the list.

text = "This, is a? random!! sentence..."

clean_text = text.split()

for i, clean in enumerate(clean_text):

    clean_text[i] = clean.strip(",.!?")

Then you can use ' '.join to (mostly) restore the list to its original form:

cleaned_text = ' '.join(clean_text)

I say "mostly", because split erases information about how many spaces were removed from the original string, which may be fine, but is worth being aware of.

The whole thing can be written using a single list comprehension.

clean_text = ' '.join([clean.strip(",.!?") for clean in text.split()])

Answer 6

Either use re and simply put r'\\w+' greedily captures all alpha characters.

>>> import re
>>> text = "This, is a? random!! sentence..."
>>> re.findall(r'\w+', text)
['This', 'is', 'a', 'random', 'sentence']   

Or you could use str.strip and str.split and an easy way to supply all punctuation to strip is using string.punctuation . This will split the text by whitespace then remove all punctuation from each sub string.

>>> from string import punctuation
>>> text = "This, is a? random!! sentence..."
>>> [s.strip(punctuation) for s in text.split()]
['This', 'is', 'a', 'random', 'sentence']   

Answer 7

Since you already good pretty good answers, I'd like to introduce regular expressions

import re
text = "This, is a? random!! sentence..."
clean_list = re.split('[.,?! ]+', text)

Where the chars inside the square brackets are the chars you want to split by and strip