根据r中的空格将一列拆分为多列
[英]Split one column into multiple based on spaces in r
问题描述
How can I split one column in multiple columns in R using spaces as separators?
如何使用空格作为分隔符将 R 中的一列拆分为多列？ I tried to find an answer for few hours (even days) but now I count on you guys to help me!我试图找到几个小时（甚至几天）的答案，但现在我指望你们帮助我！
This is how my data set looks like and it's all in one column, I don't really care about the column names as in the end I will only need a few of them for my analysis:这就是我的数据集的样子，它都在一列中，我并不真正关心列名，因为最后我只需要其中的几个来进行分析：
[1] 1000.0 246
[2] 970.0 491 -3.3 -5.0 88 2.73 200 4 272.2 279.8 272.7
[3] 909.0 1002 -4.7 -6.6 87 2.58 200 12 275.9 283.2 276.3
[4] 900.0 1080 -5.5 -7.5 86 2.43 200 13 275.8 282.8 276.2
[5] 879.0 1264 -6.5 -8.8 84 2.25 200 16 276.7 283.1 277.0
[6] 850.0 1525 -6.5 -12.5 62 1.73 200 20 279.3 284.4 279.6
Also, I tried the separate function and it give me an error telling me that this is not possible for a function class object.另外，我尝试了单独的函数，它给了我一个错误，告诉我这对于函数类对象是不可能的。
Thanks a lot for your help!非常感谢你的帮助！
2 个解决方案
解决方案1
0 2020-02-07 23:18:40
The read.table/read.csv would work if we pass it as a character vector如果我们将其作为character向量传递，则read.table/read.csv将起作用
read.table(text = data_vector, header = FALSE, fill = TRUE)
# V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11
#1 1000 246 NA NA NA NA NA NA NA NA NA
#2 970 491 -3.3 -5.0 88 2.73 200 4 272.2 279.8 272.7
#3 909 1002 -4.7 -6.6 87 2.58 200 12 275.9 283.2 276.3
#4 900 1080 -5.5 -7.5 86 2.43 200 13 275.8 282.8 276.2
#5 879 1264 -6.5 -8.8 84 2.25 200 16 276.7 283.1 277.0
#6 850 1525 -6.5 -12.5 62 1.73 200 20 279.3 284.4 279.6
data数据
data_vector <- c("1000.0 246",
"970.0 491 -3.3 -5.0 88 2.73 200 4 272.2 279.8 272.7",
"909.0 1002 -4.7 -6.6 87 2.58 200 12 275.9 283.2 276.3",
"900.0 1080 -5.5 -7.5 86 2.43 200 13 275.8 282.8 276.2",
"879.0 1264 -6.5 -8.8 84 2.25 200 16 276.7 283.1 277.0",
"850.0 1525 -6.5 -12.5 62 1.73 200 20 279.3 284.4 279.6")
解决方案2
0 2020-02-07 23:30:45
It's always easier to help if there is minimal reproducible example in the question.如果问题中有最少的可重现示例，则总是更容易提供帮助。 The data you show is not easily usable...您显示的数据不容易使用...
MRE:雷：
data_vector <- c("1000.0 246",
"970.0 491 -3.3 -5.0 88 2.73 200 4 272.2 279.8 272.7",
"909.0 1002 -4.7 -6.6 87 2.58 200 12 275.9 283.2 276.3",
"900.0 1080 -5.5 -7.5 86 2.43 200 13 275.8 282.8 276.2",
"879.0 1264 -6.5 -8.8 84 2.25 200 16 276.7 283.1 277.0",
"850.0 1525 -6.5 -12.5 62 1.73 200 20 279.3 284.4 279.6")
And here is a solution using gsub and read.csv :这是使用gsub和read.csv的解决方案：
oo <- read.csv(text=gsub(" +", " ", paste0(data_vector, collapse="\n")), sep=" ", header=FALSE)
Which produces this output:产生这个输出：
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11
1 1000 246 NA NA NA NA NA NA NA NA NA
2 970 491 -3.3 -5.0 88 2.73 200 4 272.2 279.8 272.7
3 909 1002 -4.7 -6.6 87 2.58 200 12 275.9 283.2 276.3
4 900 1080 -5.5 -7.5 86 2.43 200 13 275.8 282.8 276.2
5 879 1264 -6.5 -8.8 84 2.25 200 16 276.7 283.1 277.0
6 850 1525 -6.5 -12.5 62 1.73 200 20 279.3 284.4 279.6
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