提取斜线“/”周围数字的正则表达式

Question

I tried to extract numbers in a format like "**/*,**/*" .

For example, for string "272/3,65/5" , I want to get a list = [272,3,65,5]

I tried to use \\d*/ and /\\d* to extract 272,65 and 3,5 separately, but I want to know if there's a method to get a list I showed above directly. Thanks!

Answer 1

#importing regular expression module
import re
# input string
s = "272/3,65/5"
# with findall method we can extract text by given format
result = re.findall('\d+',s)
print(result) # ['272', '3', '65', '5']
['272', '3', '65', '5']

where the \\d means for matching digits in given input if we use \\d it gives output like below

result = re.findall('\d',s)
['2', '7', '2', '3', '6', '5', '5']

so we should use \\d+ where + matches in possible matches upto fail match

Answer 2

You can use [0-9] to represent a single decimal digit. so a better way of writing the regex would be something along the lines of [0-9]*/?[0-9]+,[0-9]+/?[0-9]* . I'm assuming you are trying to match fractional points such as 5,2/3 , 23242/234,23 , or 0,0 .

Breakdown of the main components in [0-9]*/?[0-9]+,[0-9]+/?[0-9]* :

• [0-9]* matches 0 or more digits
• /? optionally matches a '/'
• [0-9]+ matches at least one digit

My favorite tool for debugging regexes is https://regex101.com/ since it explains what each of the operators means and shows you how the regex is preforming on a sample of your choice as you write it.