正则表达式在斜杠前提取单词

Question

I'd like to extract the two words FIRST and SECOND from the phrase below, i've tried with this regex, to get the word before the slash but it doesn't work : / btw it's on python:

 import re 

    data = "12341    O:EXAMPLE (FIRST:/xxxxxx) R:SECOND/xxxxx id:1234"
    data2 = "12341    O:EXAMPLE:FIRST2:/xxxxxx) R:SECOND2/xxxxx id:1234"

    result = re.findall(r'[/]*',data)
    result2 = re.findall(r'[/]*',data2)
    print result,result2 

Answer 1

Try

result = re.findall(r'\w+:?(?=/)',data)

Explanation:

\w+   # Match one or more alphanumeric characters
:?    # Match an optional colon
(?=/) # Assert that the next character is a slash

If you don't want the colon to be part of the match (your question is unclear on this), put the optional colon into the lookahead assertion:

result = re.findall(r'\w+(?=:?/)',data)