I'd like to extract the two words FIRST and SECOND from the phrase below, i've tried with this regex, to get the word before the slash but it doesn't work : / btw it's on python:
import re
data = "12341 O:EXAMPLE (FIRST:/xxxxxx) R:SECOND/xxxxx id:1234"
data2 = "12341 O:EXAMPLE:FIRST2:/xxxxxx) R:SECOND2/xxxxx id:1234"
result = re.findall(r'[/]*',data)
result2 = re.findall(r'[/]*',data2)
print result,result2
Try
result = re.findall(r'\w+:?(?=/)',data)
Explanation:
\w+ # Match one or more alphanumeric characters
:? # Match an optional colon
(?=/) # Assert that the next character is a slash
If you don't want the colon to be part of the match (your question is unclear on this), put the optional colon into the lookahead assertion:
result = re.findall(r'\w+(?=:?/)',data)
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