Java 方法在返回值之前一直运行

Question

I'm trying to get my program to return the value after running through the last for loop, but for some reason it loops back multiple times after the for loop. I added a System.print right before return to test what was happening, and it loops many more times. The first result is what I expected, but the looping causes it the be incorrect. How can I stop this from happening?

import java.lang.Math; 
import java.util.Scanner;

public class RussianExpo 
{
    static int counter = 0;
    static int[] intArray = new int[25];
    static int value = 1;

    public static int expomod(int a, int b, int n)
    {
        while(true)
        {
            if (b == 0)
            {
                intArray[counter] = 1;
                break;
            }
            if (b==1)
            {
                intArray[counter] = a;
                break;
            }

            if (b>1)
            {
                if((b & 1) == 0); 
                {
                    intArray[counter] = 1;
                    a = (a*a);
                    b = (int) Math.floor(b/2);
                    counter++;
                    expomod(a,b,n);
                }
                if((b & 1) == 1);
                {
                    intArray[counter] = a;
                    a = (a*a);
                    b = (int) Math.floor(b/2);
                    counter++;
                    expomod(a,b,n);
                }
            }
        }

        for (int i = 0; i < 25; i++)  
        {
            if(intArray[i]>0)
            {
                value = value*intArray[i];
                value = value % n;
            }
        }
        System.out.println(value);
        return value; 
    }

    public static void main(String[] args) 
    {
        Scanner SC = new Scanner(System.in);
        System.out.println("Enter a");
        int a = SC.nextInt();
        System.out.println("Enter b");
        int b = SC.nextInt();
        System.out.println("Enter n");
        int n = SC.nextInt();

        System.out.println(expomod(a,b,n));

        SC.close();
    }

}

Output:

Enter a
30
Enter b
2
Enter n
35

25
30
15
15

Answer 1

How about setting a break within the for loop to exit the loop? Set the break after value = value % n;

Answer 2

Could be wrong, I'm not sure what the intention of the program is, but I think your issue is the recursive calls

 if((b & 1) == 1);
                {
                    intArray[counter] = a;
                    a = (a*a);
                    b = (int) Math.floor(b/2);
                    counter++;
                    expomod(a,b,n); //This recalls the function!
                }

If the first value is correct then it would appear to be the answer after the function has run it's complete course, the subsequent values come from the returns as the stack returns from the recursive calls, removing the expomod(a,b,n) call from inside the expomod() function may fix this issue.

Short answer:

remove any calls to expomod(a,b,n) from inside expomod() and see if you get the result you want.