[英]Python - Pandas - Replace a string from a column based on the value from other column - Dealing with substrings
Based on the following post: Python - Pandas - Replace a string from a column based on the value from other column基于以下帖子: Python - Pandas - 根据其他列的值替换列中的字符串
I was doing some similar on my side and I have faced new challenges.我也在做一些类似的事情,我面临着新的挑战。 I use the same example as the previous post.
我使用与上一篇文章相同的示例。
The new challenge that consists with the substrings.由子串组成的新挑战。
Imagine that I have the following dataframe:想象一下,我有以下数据框:
What I am trying is to replace on col2 the values that exists on col0 with the values from col2.我想要的是用 col2 中的值替换 col2 上存在的 col0 值。
If I use the code (it is the same from the previous post):如果我使用代码(与上一篇文章相同):
df['col3'] = df['col1'].replace(df['col0'].values, df['col2'].values, regex = True)
I will return the following dataframe:我将返回以下数据框:
And what I am trying is the following one:我正在尝试的是以下一个:
Can I add some more precision on .values to achieve this?我可以在 .values 上添加更多精度来实现这一点吗?
Thanks!谢谢!
Use re.sub
with replace by rows in DataFrame.apply
:使用
re.sub
和DataFrame.apply
的行DataFrame.apply
:
import re
df['col3'] = df.apply(lambda x: re.sub(x['col0'],x['col2'],x['col1']), axis=1)
Or in list comprehension:或者在列表理解中:
df['col3'] = [re.sub(a,c,b) for a,b,c in df[['col0','col1','col2']].to_numpy()]
print (df)
col0 col1 col2 col3
0 Table 1 Tablename: Table 1 Table A Tablename: Table A
1 Table 2 Tablename: Table 2 Table B Tablename: Table B
2 Table 2_1 Tablename: Table 2_1 Table C Tablename: Table C
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