熊猫返回具有匹配子字符串到字符串的行

Question

I have a dataframe where i want to check for every row if one column of substring is contained in another column of string. If a character in Subposition column exists in the string of Position column, return True, other wise return False in the Check column. (L = left, R = Right , S = straight, U = u turn)

 Position   Subposition  Check
   L           R         False 
   L           L         True
   LR          L         True
   SRU         L         False

Answer 1

You can zip the 2 columns and check if the second row is in the first via a list comprehension which should be pretty fast:

df['Check' ] = [b in a for a,b in zip(df['Position'],df['Subposition'])]
print(df)

---

  Position Subposition  Check
0        L           R  False
1        L           L   True
2       LR           L   True
3      SRU           L  False