附加字符串以匹配 substring

Question

I have the following string我有以下字符串

test = "if row['adm.w'] is 'Bad' and row['rem'] not empty"

I want to add str(...) for those tokens which are row[...] , how can I do this in regex?我想为那些是row[...]的标记添加str(...) ，我该如何在正则表达式中做到这一点？ I came up with this and it's not working as intended:我想出了这个，但它没有按预期工作：

re.sub(r"'([^row[']*)'", r"str(['\1'])", test)

I want the end result to be我希望最终结果是

test = "if str(row['adm.w']) is 'Bad' and str(row['rem']) not empty"

Answer 1

This should work:这应该有效：

>>> re.sub(r"(row\[.*?\])", r"str(\1)", test)
"if str(row['adm.w']) is 'Bad' and str(row['rem']) not empty"

附加字符串以匹配 substring

问题描述

1 个解决方案

解决方案1
2 2021-11-25 05:42:47

附加字符串以匹配 substring

问题描述

1 个解决方案

解决方案1 2 2021-11-25 05:42:47

解决方案1
2 2021-11-25 05:42:47