有人能告诉我如何只对嵌套在我的 JavaScript 数组中的一些项目求和吗？

Question

I am not very proud of this codeㅠㅠ I have 6000 objects in the array and would like to sum only 10 items from the array. Now I am putting ten coding blocks to the program.

Someone can tell me how to make it look like programing?

<Text style={styles.text}>[{Number((items.find( x => x.id === indexTwoId+101).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+102).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+103).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+104).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+105).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+106).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+107).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+108).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+109).as==='1'?'1':'0'))+Number((items.find( x => x.id === indexTwoId+110).as==='1'?'1':'0'))}/10]</Text>

My array is as follows;

    count: 1,
    categories: [
        {id:1,as:0},
        {id:2,as:0},
        {id:3,as:0},
        {id:4,as:0},
        {id:5,as:0},
        {id:6,as:0},
        {id:7,as:0},
        {id:8,as:0},
        {id:9,as:0},
        {id:10,as:0},
.
.
.
.]}```

Answer 1

I don't have experience with React, but in "regular" JS you might do something like this:

let sum = items.reduce((item, total) => {
    if (item.id < indexTwoId + 101 || item.id > indexTwoId + 110) return total;
    if (item.as === '1') return total + 1;
    return total;
}, 0)

You can probably "translate" it to a single line with ternary operators.

EDIT: If you just want to count items by criteria then:

items.filter(x => x.id >= indexTwoId + 101 && x.id <= indexTwoId + 110 && x.as === '1').length