在python中查找最后一个文件名

Question

I have same file name eg: filename1, filename2 , filename3, filename4 ..... filename10

I want to find last file of that specific name over here last file name is filename10

import os
import datetime
import re

files = []
for file in os.listdir("C:\\Users\\Mayur Pawar\\Desktop\\FTP work"):
    if file.endswith(".csv"):
        files.append(file)
#s = sorted(files)

#print(files)

sorted(files)

Answer 1

you can use the built-in function max :

import re

last_file = max(files, key=lambda x: int(re.search(r'\d+', x).group()))

Answer 2

You can use a Regex to do this. Not the most beautiful code ever, but it works. However, if filename has other number, you may need a more complex regex:

import re

files = ["filename10", "filename2", "fileename3"]

highest = 0
filename = ""
for f in files:
    dd = re.search(r'\d+', f)
    filenumber = int(dd.group())
    if filenumber > highest:
        highest = filenumber
        filename = f