[英]Find the file name using python
I have a file with the following format in filename.txt file.我在 filename.txt 文件中有一个具有以下格式的文件。
h:\abc\abc_Foldhr_1\hhhhhhhhhh8db
h:\abc\abc_Foldhr_1\hhhhhhhhhh8dc
h:\abc\abc_Foldhr_1\hhhhhhhhhh8dx
h:\abc\abc_Foldhr_1\hhhhhhhhhh8du
h:\abc\abc_Foldhr_1\hhhhhhhhhh8d4
h:\abc\abc_Foldhr_1\hhhhhhhhhh8d5
h:\abc\abc_Foldhr_1\hhhhhhhhhh8d6
h:\abc\abc_Foldhr_1\hhhhhhhhhh8d7
h:\abc\abc_Foldhr_1\hhhhhhhhhh8d8
I was able to read it well but unable to store in pandas data frame or the list or dictionary.我能够很好地阅读它,但无法存储在 Pandas 数据框或列表或字典中。
import pandas as pd
#data = pd.read_excel ('/home/home/Documents/pythontestfiles/HON-Lib.xlsx')
data = pd.read_table('/home/home/Documents/pythontestfiles/filename.txt', delim_whitespace=True, names=('A'))
df = pd.DataFrame(data, columns= ['A'])
print(df)
and would like to list out the filename only as并且只想列出文件名
hhhhhhhhhh8db
.
.
.
hhhhhhhhhh8d6
hhhhhhhhhh8d7
hhhhhhhhhh8d8
the purpose of storing in any data frame or dictionary is to compare against the excel file result.存储在任何数据框或字典中的目的是与 excel 文件结果进行比较。
Using split()
:使用
split()
:
res = []
with open('filename.txt', 'r') as file:
content = file.readlines()
for line in content:
# print(line.split('\\')[-1]) # to print each name
res.append(line.split('\\')[-1]) # append the name to the list
print(res)
EDIT :编辑:
Elaborating on the answer given, the split()
method being applied on the string splits it by the \\\\
, Consider the following example:详细说明给出的答案,应用于字符串的
split()
方法通过\\\\
将其拆分,考虑以下示例:
s = 'h:\abc\abc_Foldhr_1\hhhhhhhhhh8db'
print(s.split('\\'))
Which gives the output:这给出了输出:
['h:\x07bc\x07bc_Foldhr_1', 'hhhhhhhhhh8db']
The [-1]
index grabs the last element in it, hence: [-1]
索引获取其中的最后一个元素,因此:
print(s.split('\\')[-1])
Would give:会给:
hhhhhhhhhh8db
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