Find the file name using python

Question

I have a file with the following format in filename.txt file.

h:\abc\abc_Foldhr_1\hhhhhhhhhh8db

h:\abc\abc_Foldhr_1\hhhhhhhhhh8dc

h:\abc\abc_Foldhr_1\hhhhhhhhhh8dx

h:\abc\abc_Foldhr_1\hhhhhhhhhh8du

h:\abc\abc_Foldhr_1\hhhhhhhhhh8d4

h:\abc\abc_Foldhr_1\hhhhhhhhhh8d5

h:\abc\abc_Foldhr_1\hhhhhhhhhh8d6

h:\abc\abc_Foldhr_1\hhhhhhhhhh8d7

h:\abc\abc_Foldhr_1\hhhhhhhhhh8d8

I was able to read it well but unable to store in pandas data frame or the list or dictionary.

import pandas as pd

#data = pd.read_excel ('/home/home/Documents/pythontestfiles/HON-Lib.xlsx')
data = pd.read_table('/home/home/Documents/pythontestfiles/filename.txt', delim_whitespace=True, names=('A'))
df = pd.DataFrame(data, columns= ['A'])
print(df)

and would like to list out the filename only as

hhhhhhhhhh8db

.

.

.

hhhhhhhhhh8d6

hhhhhhhhhh8d7

hhhhhhhhhh8d8

the purpose of storing in any data frame or dictionary is to compare against the excel file result.

Answer 1

Using split() :

res = []
with open('filename.txt', 'r') as file:
      content = file.readlines()
      for line in content:
            # print(line.split('\\')[-1])    # to print each name
            res.append(line.split('\\')[-1]) # append the name to the list
print(res)

EDIT :

Elaborating on the answer given, the split() method being applied on the string splits it by the \\\\ , Consider the following example:

s = 'h:\abc\abc_Foldhr_1\hhhhhhhhhh8db'

print(s.split('\\'))  

Which gives the output:

['h:\x07bc\x07bc_Foldhr_1', 'hhhhhhhhhh8db']

The [-1] index grabs the last element in it, hence:

print(s.split('\\')[-1]) 

Would give:

hhhhhhhhhh8db