[英]How to get the rows in Pandas dataframe with datetime index using another datetime index?
I have a Pandas dataframe with the following datetime index:我有一个带有以下日期时间索引的 Pandas 数据框:
DatetimeIndex(['2020-01-02', '2020-01-03', '2020-01-06', '2020-01-07',
'2020-01-08', '2020-01-09', '2020-01-10', '2020-01-13',
'2020-01-14', '2020-01-15',
...
'2020-01-17', '2020-01-21', '2020-01-22', '2020-01-23',
'2020-01-24', '2020-01-27', '2020-01-28', '2020-01-29',
'2020-01-30', '2020-01-31'],
dtype='datetime64[ns]', name='Date', length=49098, freq=None)
I want to get the rows which intersect with the following datetime index:我想获取与以下日期时间索引相交的行:
DatetimeIndex(['2020-01-02', '2020-01-03', '2020-01-06', '2020-01-07',
'2020-01-08', '2020-01-09', '2020-01-10'],
dtype='datetime64[ns]', name='Date', freq=None)
What is the most natural (aka "Pythonic") way to do it?最自然(又名“Pythonic”)的方法是什么?
Use Index.intersection
:使用
Index.intersection
:
idx = idx1.intersection(idx2)
Or, if the indexes have not been previously defined:或者,如果之前未定义索引:
idx = df1.index.intersection(df2.index)
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