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如何删除字符串列表中的单词

[英]How to get rid of a word in a list of strings

Currently I am having this kind of a list:目前我有这样的清单:

['Rating 3.9577555469954', 'Rating 3.730694980695', 'Rating 4.0717869548437', 'Rating 4.0597014925373', 'Rating 3.7323798994975']

I am trying to get rid of the 'Rating ' part.我试图摆脱“评级”部分。 How do I achieve that in the end there are only numbers/floats in my list?我如何最终实现我的列表中只有数字/浮点数?

An alternative to jordanm's answer using regex :使用regex替代 jordanm 的答案:

import re
strings = ['Rating 3.9577555469954', 'Rating 3.730694980695', 'Rating 4.0717869548437', 'Rating 4.0597014925373', 'Rating 3.7323798994975']
floats = [float(re.findall('([0-9]+[,.]+[0-9]+)',x)[0]) for x in strings]
print(floats)

Outputs:输出:

[3.9577555469954, 3.730694980695, 4.0717869548437, 4.0597014925373, 3.7323798994975]

This will capture all digits, regardless of "Rating" or other word that might precede it.这将捕获所有数字,而不管它前面的“评级”或其他单词。 (in case there's Ratings for example) (例如,如果有Ratings

Loop through list and strip the value.循环遍历列表并剥离值。 I like to use UPPER or LOWER to catch all cases.我喜欢使用 UPPER 或 LOWER 来捕获所有情况。

my_list = ['Rating 3.9577555469954', 'Rating 3.730694980695',
           'Rating 4.0717869548437', 'Rating 4.0597014925373', 'Rating 3.7323798994975']

new_list = []

for value in my_list:
    new_list.append(value.upper().strip('RATING').strip())

print(new_list)

Results:结果:

['3.9577555469954', '3.730694980695', '4.0717869548437', '4.0597014925373', '3.7323798994975']

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