How to get rid of a word in a list of strings

Question

Currently I am having this kind of a list:

['Rating 3.9577555469954', 'Rating 3.730694980695', 'Rating 4.0717869548437', 'Rating 4.0597014925373', 'Rating 3.7323798994975']

I am trying to get rid of the 'Rating ' part. How do I achieve that in the end there are only numbers/floats in my list?

Answer 1

An alternative to jordanm's answer using regex :

import re
strings = ['Rating 3.9577555469954', 'Rating 3.730694980695', 'Rating 4.0717869548437', 'Rating 4.0597014925373', 'Rating 3.7323798994975']
floats = [float(re.findall('([0-9]+[,.]+[0-9]+)',x)[0]) for x in strings]
print(floats)

Outputs:

[3.9577555469954, 3.730694980695, 4.0717869548437, 4.0597014925373, 3.7323798994975]

This will capture all digits, regardless of "Rating" or other word that might precede it. (in case there's Ratings for example)

Answer 2

Loop through list and strip the value. I like to use UPPER or LOWER to catch all cases.

my_list = ['Rating 3.9577555469954', 'Rating 3.730694980695',
           'Rating 4.0717869548437', 'Rating 4.0597014925373', 'Rating 3.7323798994975']

new_list = []

for value in my_list:
    new_list.append(value.upper().strip('RATING').strip())

print(new_list)

Results:

['3.9577555469954', '3.730694980695', '4.0717869548437', '4.0597014925373', '3.7323798994975']