减少和 object 解构/赋值

Question

Let's assume I have two simple objects and I want to create a third one that will be joining their properties. This works perfectly:

(()=>{
  const a1 = {a: 2, b: 3}
  const b1 = {a: 100, c: 5}
  return {...a1, ...b1}
})()
// { a: 100, b: 3, c: 5 }

But it stops working once I try to create a new object derived from b1 using .reduce . For a sake of simplicity let's create a reduce function that simply makes a shallow copy of the b1 object:

 let r = (()=>{ const a1 = {a: 2, b: 3} const b1 = {a: 100, c: 5}, b2 = Object.entries(b1).reduce((acc, [key, value])=>Object.defineProperty(acc, key, {value}), {}) console.log(b2) // {a: 100 c: 5} return {...a1, ...b2} })() console.log(r);// { a: 2, b: 3 }

I have a feeling that there is something about .reduce function that I just don't understand. What can I do to fix this?

Answer 1

By default, properties created with defineProperty are not enumerable, so they won't be included with a spread.

To fix:

b2 = Object.entries(b1).reduce((acc, [key, value]) =>
  Object.defineProperty(acc, key, {value, enumerable: true})
, {})

Answer 2

You should mark the property as enumerable

Object.defineProperty(acc, key, {value, enumerable: true});

Why not just using the function Object.assign instead, it's straightforward.

 let r = (()=> { const a1 = {a: 2, b: 3}; const b1 = {a: 100, c: 5}; const b2 = Object.entries(b1).reduce((acc, [key, value]) => Object.assign(acc, {[key]: value}), {}) console.log(b2); // {a: 100 c: 5} return {...a1, ...b2} })() console.log(r); // { a: 2, b: 3 }

Answer 3

One fix could be to use Object.assign to create a copy of b1 like:

 let r = (()=>{ const a1 = {a: 2, b: 3} const b1 = {a: 100, c: 5} const b2 = Object.assign({}, b1) console.log(b2) // {a: 100 c: 5} return {...a1, ...b2} })() console.log(r); // { a: 100, b: 3, c: 5 }