将 1000 条回归线添加到 ggplot 的最佳方法是什么？ （基于模型的引导）

Question

From a bootstrapping model I have 1000 sets of coefficients for this regression model:

y = b0 + b1x + b2(x^2)

What is the function call to plot a quadratic line if I already have the coefficients? IE I do not want to "fit" a linear model to my data.

I tried adding lines via a for loop to my ggplot object:

for (i in 1:1000) { 
  reg_line <- stat_function(fun=function(x) quad$coefficients[1] + 
                                      quad$coefficients[i,2]*x + quad$coefficients[i,3]*(x**2))
  reg_lines <- reg_lines + reg_line}

That didn't work - it seems to only add the last line in the loop.

The reason I want to add 1000 regression lines to my plot is because it is for a homework problem - I am well aware this is not a common use case.

Answer 1

There may be other ways to do this, but hopefully this can give you some ideas. I used the mtcars dataset and generated some bootstrap samples for modelling. You can skip this step.

library(ggplot2)
library(tidyr)
library(dplyr)

data(mtcars)

drat=seq(min(mtcars$drat), max(mtcars$drat), length.out=100)

# Bootstrap function
bs <- function() {
  df = mtcars[sample(1:nrow(mtcars), replace=TRUE),]
  lm_fit <- lm(mpg ~ drat+I(drat^2), data=df)
  data.frame(Model=predict(lm_fit, newdata=data.frame(drat))) # Replace with your own
}

foo <- replicate(10, bs()) # Simulate

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You would start from here since you should already have a data frame or list of predicted values from your 1,000 bootstrap models. Reshape it into a very long form to create a grouping column for the geom_line function.

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foo_long <- data.frame(foo, drat) %>%
  pivot_longer(cols=-drat, names_to="Model", values_to="mpg")

ggplot(data = mtcars, aes(x = drat, y = mpg)) + 
  geom_point(color='blue') +
  geom_line(data = foo_long, aes(x=drat, y=mpg, group=Model, color=Model)) +
  guides(color=FALSE)

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