[英]Use 2 exceptions in a python function
I want to write a function to calculate the mode of a column in a grouped by dataframe.我想编写一个函数来计算按数据帧分组的列的模式。 If the values of a group has not a mode, the first exception: calculate the median and if the values of the group are all null values, the second exception:do nothing.如果组的值没有众数,第一个例外:计算中位数,如果组的值都是空值,第二个例外:什么都不做。 The sample dataframe is like below:示例数据框如下所示:
dataframe = pd.DataFrame({'b':['b1','b1','b1','b1','b1','b1','b2','b2','b2','b2','b2','b2','b3','b3','b3'],'d':[0.1,None,0.12,None,None,0.13,1,2,1,1,None,None,None,None,None]})
The function is as follow:功能如下:
def fill_mode(group):
try:
group['mode'] = mode(group['d'])
except:
not_nulls = group[~group['d'].isnull()]
group['mode'] = median(not_nulls['d'])
except:
pass
return group
And the apply function is as bellow:应用函数如下:
dataframe = dataframe.groupby('b').apply(fill_mode)
Which raises this error :这引发了这个错误:
SyntaxError: default 'except:' must be last语法错误:默认 'except:' 必须是最后一个
The final output should be like this:最终的输出应该是这样的:
You need a second try/except
block.您需要第二个try/except
块。
def fill_mode(group):
try:
group['mode'] = mode(group['d'])
except:
try:
not_nulls = group[~group['d'].isnull()]
group['mode'] = median(not_nulls['d'])
except:
pass
return group
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