[英]pandas dropna() only if in first row NaN value
I have a dataframe like the following我有一个如下所示的数据框
df = [[1,'NaN',3],[4,5,'Nan'],[7,8,9]]
df = pd.DataFrame(df)
and I would like to remove all columns that have in their first row a NaN value.并且我想删除第一行中具有 NaN 值的所有列。
So the output should be:所以输出应该是:
df = [[1,3],[4,'Nan'],[7,9]]
df = pd.DataFrame(df)
So in this case, only the second column is removed since the first element was a NaN value.因此,在这种情况下,由于第一个元素是 NaN 值,因此只删除了第二列。 Hence, dropna() is based on a condition.. any idea how to handle this?因此, dropna() 是基于一个条件......知道如何处理这个吗? Thx!谢谢!
If values are np.nan
and not string NaN
( else replace them ), you can do:如果值是np.nan
而不是字符串NaN
(否则替换它们),您可以执行以下操作:
Input:输入:
df = [[1,np.nan,3],[4,5,np.nan],[7,8,9]]
df = pd.DataFrame(df)
Solution:解决方案:
df.loc[:,df.iloc[0].notna()] #assign back to your desired variable
0 2
0 1 3.0
1 4 NaN
2 7 9.0
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