python：从不同目录中的脚本调用类并获取函数

Question

I have a script that I am currently working on, named exp1.py and it's located in

/project/exp1.py 

In this script, I am trying to call a function named computelikelihood() , which is inside the class Class() , which is in script method.py , in a different directory:

 /project/methods/c_CLASS/method.py

So, in my code in exp1.py , I do this:

import sys

sys.path.append('/project/methods/c_CLASS/')

Which gets me to the folder where method.py is located, but when I want to call the Class() from the method.py , so that I get the function computelikelihood() , that I actually want, I get error. I try this:

from method import Class
from Class import computelikelihood

But I get ImportError: No module named Class . Can anyone help?

EDIT This is how the __init__ of my Class looks like:

class Class:
    def __init__(self,e2wl,w2el,label_set):
        self.e2wl = e2wl
        self.w2el = w2el
        self.workers = self.w2el.keys()
        self.examples = self.e2wl.keys()
        self.label_set = label_set

Answer 1

Since you are trying to use a method from a Class, you should do so via the class. Do not import the function alone as it isn't intended to be used as such:

from method import Class

Class.computelikelihood()

However, this only works if computelikelihood is a static/class method:

class Class:

    @classmethod
    def computelikelihood(cls):
        ...

    # or

    @staticmethod
    def computelikelihood():
        ...

If it's an instance method:

class Class:
    def computelikelihood(self):
        ...

You'll need to first instantiate an object of class Class :

from method import Class

classObject = Class()
classObject.computelikelihood()