如何清理和拆分以下字符串？

Question

I have a column in my database which stores string in the following format:

"['Action', 'Adventure', 'Comedy']"

How do I extract the movie genres so I can use them seperately, after extraction I should have the following:

g1 = 'Action'  
g2 = 'Adventure'  
g3 = 'Comedy'

Answer 1

You can try this. You can split them at every , and strip [] ' off of the word and use tuple unpacking.

a="['Action', 'Adventure', 'Comedy']"

g1,g2,g3=[i.strip(" []'") for i in a.split(',')]

---

print(g1,g2,g3)
# Action Adventure Comedy

Answer 2

If you like regex:

import re
g = "['Action', 'Adventure', 'Comedy']"
g1,g2,g3 = re.findall(r"'(\w+)'",g)
print(g1,g2,g3)

Answer 3

Try this :

inputString = "['Action', 'Adventure', 'Comedy']"

# Converting string to list 
res = inputString.strip('][').split(', ') 

g1= res[0]
g2= res[1]
g3= res[2]

There are quite a few ways to do this.

1. Using string manipulation as done above.

2. Using ast.literal_eval() .

3. Using json.loads() .

You can checkout all the examples here : https://www.geeksforgeeks.org/python-convert-a-string-representation-of-list-into-list/

Answer 4

With a bit of mangling you can use json :

import json

src = "['Action', 'Adventure', 'Comedy']"
src = src.replace("'",'"')

g = json.loads(src)
g1,g2,g3 = g

print(g1,g2,g3)

Output:

Action Adventure Comedy

Answer 5

Try this code using regex:

import re
g = "['Action', 'Adventure', 'Comedy']"
[g1, g2, g3] = " ".join(re.findall("[a-zA-Z]+", g)).split(" ")