如何从派生表中选择具有 MAX(value) 的行，其中值都是计算的总和？

Question

I have tried the following code but I just get the full table with all the names and sum values instead of one row with the max value:

SELECT stageName, max(total_salary)
FROM (
      SELECT c.*, sum(p.dailySalary) as total_salary        
      from contender as c
      left join participant as p
      on (p.contender = c.idContender)
      group by c.idContender ) b
group by stageName;

output: 
Yellow Jesters  205
TikTok  3073
Teabags 947
Bobbleheads 11840
Reddit  1486

but I just need: Bobbleheads 11840

PS: Please suggest a solution WITHOUT using desc and limit

Answer 1

If you just want to top row in your resultset, you can sort and limit:

select c.*, sum(p.dailySalary) as total_salary        
from contender as c
left join participant as p on p.contender = c.idContender
group by c.idContender
order by total_salary desc
limit 1

If there is a possibility of top tie, and you want to allow it, you can use window functions:

select *
from (
    select 
        c.*, 
        sum(p.dailySalary) as total_salary, 
        rank() over(order by sum(p.dailySalary) desc) rn
    from contender as c
    left join participant as p on p.contender = c.idContender
    group by c.idContender
) t
where rn = 1

Answer 2

Here's a solution that should work on any version of MySQL 5.x, using no ORDER BY, LIMIT, window functions, views, or CTEs.

SELECT a.stagename, a.total_salary
FROM (
      SELECT c.*, sum(p.dailySalary) as total_salary        
      from contender as c
      left join participant as p
      on (p.contender = c.idContender)
      group by c.idContender ) AS a
LEFT OUTER JOIN (
      SELECT c.*, sum(p.dailySalary) as total_salary        
      from contender as c
      left join participant as p
      on (p.contender = c.idContender)
      group by c.idContender ) AS b
  ON a.total_salary < b.total_salary
WHERE b.total_salary IS NULL;

Tested on MySQL 5.7.27.

Output:

+-------------+--------------+
| stagename   | total_salary |
+-------------+--------------+
| Bobbleheads |        11840 |
+-------------+--------------+