如何返回字典中具有最大值的键

Question

Say I have a dictionary which looks like this:

dct = {'key1':('Hello, Python!', 1), 'key2':(10, 2), 'aa':(9.9, 3)}

How do I return the key which has the highest 2nd value, ie. the highest 2nd value between 1, 2 and 3 is 3, therefore the returned key is:

'aa'

Answer 1

Sort the dictionary by values ( item[1] when you parse dct.items() ), and especially by the second element of these values ( item[1][1] ). Then your max is the first element of the sorted list.

ordered_keys = [k for k, v in sorted(dct.items(), key=lambda item: item[1][1], reverse=True)]
best = ordered_keys[0]

Answer 2

You can use max .

max(dct.items(),key=lambda x:x[1][1])
# ('aa', (9.9, 3))

If you just want 'aa'

max(dct.items(),key=lambda x:x[1][1])[0]
# 'aa'