打印从任何元素到矩阵中给定元素的最短路径的值

Question

Input data: number of rows, number of columns, and the point's coordinates
the named position will be given the value 0.
note: indexing starts from 1 (bad practice, I know, but that's the requirement)
ie: for this input 4 5 1 1 this matrix will be generated:
0 1 2 3 4
1 2 3 4 5
2 3 4 5 6
3 4 5 6 7

I don't want the code, but if someone could give me a hint or something to help, it would be greatly appreciated!! If code is easier than explaining a way to solve it, then please don't hesitate to post it.(C++) Edit: I got a solution, how could I make this faster?

#include <iostream>
using namespace std;
int main()
{
    int v[501][501], i, j, m, n, o, p;
    cin >> m >> n >> o >> p;
    for (i = o; i >= 1; i--)
            v[i][p] = o - i;
    for(i = o;i <= m; i++)
        v[i][p] = i - o;
    for(i = 1; i <= m; i++)
        for(j = 1; j <= n; j++){
            if(j < p)
                v[i][j] = -j + p + v[i][p];
            else if(j > p)
                v[i][j] = j - p + v[i][p];            
        }
    for(i = 1 ; i <= m; i++){
        for(j = 1; j <= n; j++)
            cout << v[i][j] << " ";
        cout << '\n';
    }
}

Answer 1

Try to draw the answer for a few examples and you will see a pattern that you can mimic.

For example:

5 5 3 3

4 3 2 3 4

3 2 1 2 3

2 1 0 1 2

3 2 1 2 3

4 3 2 3 4

By the way this is a standard question to solve with BFS.