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在python中是否可以从函数调用中的列表中提取变量

[英]In python is it possible to extract variables from a list inside a function call

I'm attempting to create a common create function that executes a function call to an SDK我正在尝试创建一个通用的创建函数来执行对 SDK 的函数调用

func: The SDK function is passed as my first parameter and the function itself can't be edited func: SDK函数作为我的第一个参数传递,函数本身无法编辑
request: This is a object that every create end point expects请求:这是每个创建端点都期望的对象
args: parameter list that will vary depending on the SDK function passed args:参数列表会根据传递的 SDK 函数而变化

SDK function signatures SDK函数签名
def create_a(self, create_type_a_details):
def create_b(self, extra_val_one create_type_b_details):
def create_c(self, extra_val_one, extra_val_two, create_type_c_details):


Current implementation当前实施

def create_resource(func, request, *args):

        try:
          if len(args) == 1:
            response = func(args[0], request)
          elif len(args) == 2:
            response = func(args[0], args[1], request)
          else:
            response = func(request)
        return response.data

    except ServiceError as e:
        log.error("Failed create operation {message}".format(message=e.message))
        raise e


I don't like the above solution for obvious reasons.出于显而易见的原因,我不喜欢上述解决方案。 If there is another SDK create function that takes a third parameter before the request object, I will need to add a new elif.如果有另一个 SDK 创建函数在请求对象之前接受第三个参数,我将需要添加一个新的 elif。

Is there a way I could call the SDK function with a dynamic set of parameters without editing the SDK functions to extract the values?有没有一种方法可以使用一组动态参数调用 SDK 函数,而无需编辑 SDK 函数来提取值? Can I use a Lamba inside of the function call?我可以在函数调用中使用 Lamba 吗?

thanks Donagh谢谢多纳

You may just expand args to give each element as a different parameter :您可以扩展args以将每个元素作为不同的参数:

def create_resource(func, request, *args):
    response = func(*args, request)
    return response.data

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